States101
Osceola County, Michigan Gender Ratios
Gender Ratio:
Men
Women
Total Population:
Men
Women
There are more men than women in Osceola County, Michigan. Total population of Osceola County, Michigan is estimated at 23,169 people with 11,720 male and 11,449 female. There are 271 more men than women in the county, which is 1.17% of the total population.
The Osceola County, Michigan Gender Ratio is 102 men to 100 women (102:100) or 1.02. Osceola County, Michigan's gender ratio is higher than the Michigan State average of 97 men to 100 women (97:100) or 0.97. The gender ratio is also higher than the national average of 97 men to 100 women (97:100) or 0.97.
Osceola County, Michigan Gender Ratios By Age
Gender Ratios vary by age group as well as location. The table below shows the gender ratios breakdown in Osceola County, Michigan by age.
| Age Range | Osceola County Ratio | Michigan State Ratio | Nationwide Ratio |
|---|---|---|---|
| 0 to 4 | 106 to 100 | 105 to 100 | 104 to 100 |
| 5 to 9 | 114 to 100 | 105 to 100 | 104 to 100 |
| 10 to 14 | 113 to 100 | 104 to 100 | 104 to 100 |
| 15 to 19 | 109 to 100 | 105 to 100 | 105 to 100 |
| 20 to 24 | 114 to 100 | 103 to 100 | 105 to 100 |
| 25 to 29 | 103 to 100 | 102 to 100 | 100 to 100 |
| 30 to 34 | 98 to 100 | 99 to 100 | 100 to 100 |
| 35 to 39 | 103 to 100 | 99 to 100 | 100 to 100 |
| 40 to 44 | 100 to 100 | 98 to 100 | 100 to 100 |
| 45 to 49 | 118 to 100 | 98 to 100 | 100 to 100 |
| 50 to 54 | 99 to 100 | 97 to 100 | 100 to 100 |
| 55 to 59 | 94 to 100 | 95 to 100 | 93 to 100 |
| 60 to 64 | 105 to 100 | 93 to 100 | 93 to 100 |
| 65 to 69 | 98 to 100 | 91 to 100 | 79 to 100 |
| 70 to 74 | 96 to 100 | 87 to 100 | 79 to 100 |
| 75 to 79 | 95 to 100 | 80 to 100 | 79 to 100 |
| 80 to 84 | 75 to 100 | 68 to 100 | 79 to 100 |
| 85 and over | 60 to 100 † | 51 to 100 | 79 to 100 |
Cities in Osceola County, Michigan
Gender Ratios on this page are an aggregate of the gender ratios in the following cities within the region:
Evart, Hersey, Leroy, Reed City, Sears, and Tustin.